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Research Notes I, 1949
9
Compare two signals in the same magnetic field:
signal height recorded by the milliammeter
= C[j(j+1)γ^4 / (width)^2] (Molarity) (percent Abundance)
For Cd μCd = 0.65 j=1/2 NaCl 5.5 M
Na μNa = 2.215 j=3/2 CdCl2 2 [M]
(Signal/noise) ratio for Na observed in scope ~ [1₀?]
(Signal/noise) ratio for Cd recorded in meter ~0.0565 x 200 = 11.3 assuming 200 times enhanced.
10
August 6, 1949
Test of the size of the signal of na in 0.428 M NaCl soln plus 0.8 M MnSO₄. Hs = 0.8 gauss, Gain - 56, sweep freq = 91cps φ = 100
| No. of cells in the β-supply of oscillator | H₁ | Signal Ht | width |
|---|---|---|---|
| 1 | 86, 82, | 2 mm | |
| 1 1/2 | 30 | " | |
| 2 | 5 | " |
Using 0.2 M NaCl without adding Mn [bit?], under the same conditions as above (Hs = 0.8 gauss, gain - 56, H₁ corresponds to one cell) signal Ht = 4.5, 5.0, 4.5 width = (2mm)-
[Break]
Test: 0.1 M soln of NaCl was prepared by adding 0.2 M MnSO₄.
37
Sept. 8, '49
H₂PtCl₆ ⋅ 6 H₂O 5% soln 27.6 c.c.
H₂PtCl₆ ⋅ 6 H₂O evaporated to dryness turned to a dark brown substance, which was dissolved in HCl & conc. H₂SO₄. Added NH₄OH to the soln. A yellow precipitate was obtained. It is (NH₄)₂PtCl₆. Evaporated the filtrate. Precipitated again with NH₄OH. Repeated 3 times until not too much pt left in soln (the color of soln is very light). Fused (NH₄)₂PtCl₆ in a crucible. Platinum sponge was obtained. It weighed 684 mg Dissolved Pt sponge in aqua regia.
H₂PtCl₆ ⋅ 6 H₂O recovered.
29.334 28.650 0.684 gm Pt
38
Sept. 12, '49
Preparation of Enriched CdIII Sample
Quantity 1.5 gms of CdS (M.W. = 144.47) ~ 80% of CdIII.
Will prepare 3 c.c. of CdSO₄ soln: Molarity = = 3.46 ✓
(a) CdSO₄ will be obtained by boiling CdS in 20% H₂SO₄.
(b) Add sufficient amount of MnCl₂ into it
[Break]
Recovery of CdS
(a) CdSO₄ + MnCl₂ soln will be [blank space] by NH₄OH
(b) Mn will be Manganous salt will be oxidized to manganic salt & precipitated out by HMn₄OH KMnO₄ which will be added such that the soln appears a little bit biolet.
(c) After filtering out the manganic salt, decolor [thi?] soln by adding a little K₂⋅O₂
39
(d) CdS will be precipitated out by passing H₂S thru the filtrate.
(e) In order to avoid loss of CdS by filtering the soln will be sucked out by & washed by water several times.
(f) CdS will be dried in a vacuum decicator.
Solubility of CdS per 100 gms of H₂O =0.00013
Loss of CdS by washing 10 times with 100 ml H₂O = 1-(0.99987)10 = 1-0.9987 = 0.0013 = 0.13%
