3
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Transcription
Status: Needs Review
µ (D²) = 0.857631 ± 0.00011 µN
K. Lindstrom
using NaBr, Na2BrO4 solution
µ(S33) = 0.63 ± 0.02
spin 3/2
spin of Se77 1/2
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µ (D²) = 0.857631 ± 0.00011 µN
K. Lindstrom
using NaBr, Na2BrO4 solution
µ(S33) = 0.63 ± 0.02
spin 3/2
spin of Se77 1/2
Please sign in to write a note for this page