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Facsimile
Transcription
Status: Needs Review
V ( Sn 115 ) = 6236.4 ( 1 + 5X10-5 )
V ( Na 23 ) = 5044.6 ( 1+ 4X10-5 )
V ( Sn 115 ) = 6236.4 ( 1+ 6.2 x 10-5 )
V ( Na 23 ) = 5044.6
= 1.23625 ( 1+ 6.2 x10 -5 ) = 1.23625 (1+0.00006 )
= 1.23625 + 0.000076
Data obtained by WP
V (Sn 119 ) = 1.4090 + 0.0005
V ( Na 23 )
V ( Sn 117 ) = 1.3464 + 0.0004
V ( Na 23 )
V ( Sn 119 ) = 1.0465 + 0.0003
V ( Sn 119 )
M ( Sn 117 ) = - 1.0000 + 0.0009 MN
M (Sn 119 ) = - 1.0466 + 0.0009 MN
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