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Status: Needs Review

August 30, '49

Block pointed out that, if γT2 = T1γ² = [const] as
would be the case for termal broadening of the Sn isotopes,
that our isotope identification would be backwards,
since it turns out that

dv/dΔω hmax = -γ²([const.])T2²

[Now it] T2 = 1/γΔH and ΔH = kH, then T2 = 1/γkH = 1/kΔω
& since we compare at [const.] freq, T2 = [const] [therefore] our
γ² correction is correct on opposite page.

Test
Sample #5
A (5075 [right arrow] 5050)


Width Dist. Marker Res. Dist. (Markers)
3.0 mm 111.8 mm 20.5 mm
3.1
3.2
2.7 ν = 5070.5 KC
3.4
3.0 rate = 25/111.8 = 0.222 KC/mm
3.1
Av. = 3.07 ± 0.21
= 3.07 (1 ± 0.07) mm

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