115

Atomic wt of nitrogen in 31.4% enriched N¹⁵
= 14.00751 × 0.686 + 15.00489 × 0.314 = 14.321

Gauss of HNO₃ solⁿ = 12.9 containing 10.57% nitric acid by wt.

Gauss of HNO₃ = 0.1057 × 12.9 = 1.3635

Moles of HNO₃ = 1.3635/63.329 = 0.02153

Molecular wt of NaNO₃ = 85.32

Wt. of NaNo₃ = 85.32 × 0.02153 = 18.34 1.834 grams

Solⁿ of NaNO₃ = 3.5 c.c.

Molar of solⁿ =