116
Facsimile
Transcription
Status: Needs Review
in NaNo3 = 1.04274 1.40274 ± 0.000057
in NH3 {{tex: $\frac{\gamma(N^{15})}{\gamma(N^{14})}$ :tex}}= 1.04261 1.40261 ± 0.00006 ± 0.00008
Notes and Questions
Nobody has written a note for this page yet
Please sign in to write a note for this page