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member of the triplet is a member of the pair. That is manifestly absurd. But it strikes the mind as a different kind of absurdity from a self-contradiction, say like that about Arthur and the pictures. This impression deserves careful examination.

We remark that if the member of the triplet and or the pair were mere predicates or general subdivisions, there would be no absurdity. It is not absurd to say that every special science is either nomological, classificator, or descriptive, and is at the same time either physical or psychical; although to Aristotle this seemed impossible when the predictions were essential.

Let us see how it will be if from that graph we remove the junctures and simply

Last edit almost 4 years ago by Lilith27
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and simply leave a triplet of graphs and a pair of graphs. The graph will then become, let us say, this:

[encode formula or diagram in LaTeX ??]

On testing this by the rule given in the last lecture, we find that the graph is perfectly possible, as it stands, but that it will cease to be possible if more than one of the triplet p, q, r, are true or if more than one of the pair m, n are true, as is obvious on inspection. This suggests that the absurdity of the first graph is due, not to the relation of the identity, but to the fact

Last edit almost 4 years ago by Lilith27
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[encode formula or diagram in LaTeX ??]

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of existence positive existence of the members of the triplet and of the pair. In order to test this let us substitute in that graph some of other relation for that of identity. Let us assert first that there are three individuals, each of which, instead of being non-identical with each of the others, does not stand in a [certai] an undefined reciprocal relation to the others which we will represent by [encode formula or diagram in LaTeX ??] that is A is r to B and B is r to A. This will give us. And we will add that each of these tripplets is a member of the second triplet We will write instead of adding that each of these is a member of a certain triplet will simply say [thus ??] they agree in some is a member of the triplet having a certain graph true of them. We shall t to mean "is a member of the triplet in question This will give us [encode formula or diagram in LaTeX ??] We will have then this graph (on opposite page)

Last edit almost 4 years ago by Lilith27
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Next, let us assert -p is a member of a pair and assert that there are not three members of the pair that do not stand in this recriprocal relation each to both the others ; or in other words take

Next instead of talking of a pair, let us talk of individuals of whom a certain graph -p is true, and say that it is not true that there are three of these related to one another take the three of which of which t is true. This will give us

[encode formula or diagram in LaTeX ??]

Now we have to assert something or [or questionable absurd. ??] concerning the relation between t and p.

Last edit almost 4 years ago by Lilith27
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