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All U is the foresent U
All U is P
therefore
All [Dr?] U is P
No rather
The foresent U is U
The present U is P
therefore All U is P
Now we have | why not then |
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All S is S | S S' S" are taken as U |
Some S is M | therefore M is S or S' or S" |
Some M is S | S S' S" is P |
Why yes! This is it.
Induction consists in that very conversion which Aristotle says is necessary [Dr?] its validity.
The inference is _
2 that if - S S'S" occur only in consequence of being M
2' then All U has the common characters of S S' S"
Some S is M
Zen _ now to hypothesis * Fig 2
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M is P
S is M
S is P ________________^__________________ S is P M is P S is M S is P M is P S is M ________________________________________
Some S is not P | All M is P |
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All S is P | All M is not P |
All S is M | Some S is not P |
Some S is M | All S is P |
Some M is not P | Some S is not M |
Some M is P | All S is not M |
__ | __ |
Some S is found P | S is P P' P" |
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S is taken as M | S is M |