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Example 2nd Continues

Sta	Bearings	Changed Bearings	District	N	S	E	W

A B	S 40 1/2E	N85 1/2E	31.8.0	2.49	-	31.7
B C	N 54 E	North	(2.08)	(2.08)
C D	N29 1/4E	N24 3/4W	2.21	2.01			0.93
D E	N(28 3/4)E	N(25 1/4)W	35.35	(31.98)			(15.08)
E F	N 57W	S 69W	20.90		7.49		19.51
F A	S47W	S7E	31.30		31.07	3.82
			36.48	38.56	35.52	20.44
				36.48	20.44
				____	_____
				2.08	15.08

As side ED 35.35 ------------------ 8.45161
As to side GD 15.08---------------1.17840
So is sine L EGD 90 ---------------10.00000
________
To sine L DEG 25.15---------- 9.63001

Example 2nd. Given the bearings and distances of the sides of a tract of land as follow; 1st Sunknown E
31.80 ch, 2n N 54 E 2.08 ch; 3rd N 29 1/4 E 22. ch: 4th N 28 3/4 E
35.35 ch3 5th N 57 W 20.90 ch; and 6th Sunknown W 31.30
To th eplace of beginning. Required the unknown bearings.
Ans 1st S 40 [degree mark] .29'E; and 6th S 4 7 [degree mark] W.