9

Compare two signals in the same magnetic field:

signal height recorded by the milliammeter

= C[j(j+1)γ^4 / (width)^2] (Molarity) (percent Abundance)

For Cd μCd = 0.65 j=1/2 NaCl 5.5 M

Na μNa = 2.215 j=3/2 CdCl₂ 2 [M]

(Signal/noise) ratio for Na observed in scope ~ [1₀?]

(Signal/noise) ratio for Cd recorded in meter
~0.0565 x 200 = 11.3
assuming 200 times enhanced.